5p^2-10p+1.8=0

Solution for 5p^2-10p+1.8=0 equation:

5p^2-10p+1.8=0

a = 5; b = -10; c = +1.8;
Δ = b2-4ac
Δ = -102-4·5·1.8
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-8}{2*5}=\frac{2}{10}
=1/5
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+8}{2*5}=\frac{18}{10}
=1+4/5
$